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Wednesday, December 30, 2015
Tuesday, February 05, 2013
Free downloads:Electrical & Electronic Engineering books
Free downloads:Electrical & Electronic Engineering books
http://bookboon.com/en/textbooks/it-programming
http://bookboon.com/en/textbooks/it-programming
Monday, February 04, 2013
Areas of Geometric Shapes
Square
A = a2 (1a)
a = A1/2 (1b)
d = a 21/2 (1c)
Rectangle
A = a b (2a)d = (a2 + b2)1/2 (2b)
Parallelogram
A = a h= a b sin α (3a)d1 = ((a + h cot α)2 + h2)1/2 (3b)d2 = ((a - h cot α)2 + h2)1/2 (3b)
Equilateral Triangle
A = a2/3 31/2 (4a)
h = a/2 31/2 (4b)
Triangle
A = a h / 2= r s (5a)r = a h / 2s (5b)R = b c / 2 h (5c)s = (a + b + c) / 2 (5d)x = s - a (5e)y = s - b (5f)z = s - c (5g)
Trapezoid
A = 1/2 (a + b) h= m h (6a)m = (a + b) / 2 (6b)
Hexagon
A = 3/2 a2 31/2 (7a)
d= 2 a
= 2 / 31/2 s
= 1.155 s (7b)
s = 31/2 / 2 d
= 0.866 d (7c)
Circle
A = π/4 d2= π r2= 0.785.. d2 (8a)U = 2 π r= π d (8b)
Sector and Segment of a Circle
Sector of Circle
Area of a sector of circle can be expressed as
A = 1/2 θr r2 (9)= 1/360 θd π r2whereθr = angle in radiansθd = angle in degrees
Segment of Circle
Area of a segment of circle can be expressed as
A = 1/2 (θr - sin θr) r2= 1/2 (π θd/180 - sin θd) r2 (10)
Right Circular Cylinder
Lateral surface area of a right circular circle can be expressed as
A = 2 π r h (11)whereh = height of cylinder (m, ft)r = radius of base (m, ft)
Right Circular Cone
Lateral surface area of a right circular cone can be expressed as
A = π r l= π r (r2 + h2)1/2 (12)whereh = height of cone (m, ft)r = radius of base (m, ft)l = slant length (m, ft)
Sphere
Lateral surface area of a sphere can be expressed as
A = 4 π r2 (13)
Saturday, July 24, 2010
Cisco Network Devices
For all company and user,
we have a different type of cisco network devices , with low price.
so if any one need any network device send email to us at:-
elsayed@zakq8.com
elsayed_fouad@yahoo.com
we have a different type of cisco network devices , with low price.
so if any one need any network device send email to us at:-
elsayed@zakq8.com
elsayed_fouad@yahoo.com
Friday, June 18, 2010
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